Res/342 Ii

There are five standards to the conjecture studying. The beginning(a) measuring is to utter the cryptograph & alterative supposal, the second step is finding the lessened appreciate, third step is to calculate the raise statistic, the fourth step is to compare the test to the vital tally and the fifth disk operating system is the results. The team allow analyze the stack away info to decide if 10 percent or more(prenominal) of Central field Bank checking account customers in metropolis 1and 2 is victimization its ATM. tonicity matchless: responsibility the hypothesis. The Null hypothesis is the dictation that is believed to be true and is shown as? H?_0. The Alternative Hypothesis maybe true if the Null hypothesis is rid ofed and is shown as H_1. To show the hypothesis from above in this numerical organise would be this: H_0 ? ? .10 H_1 ? < .10 Step Two: bring forth the critical value. To be able to find the Z critical value, one must know the signifi cance value for this expression of a one-tailed test a significance level of 0.05 will be apply which gives a Z critical value of 1.753. logical implication Level is 0.05 Z Critical Value is 1.753 worsen H_(0 )if z less than 1.

753 otherwise do not reject H_0 Step Three: Calculate the test Statistic. The formula used and mould is shown below t=(¯x_1-¯x_2)/(?((s_1^2)/n_1 )+(s_2^2)/n_2 ) City 1City 2 ¯x_= 9.37¯x_ = 11 n=16n=16 s=25s=20 t=(9.37-11)/(?(?25?^2/18)+?25?^2/18) (-1.63)/(?(625/16)+625/16) (-1.63)/?(39.06+39.06) (-1.63)/?78.12 (-1.63)/8.84 .18 Step 4: Compare the test to the critical value. Since the t = 0.18 Step basketball team: State the results. Since z is less than 1.753 H_0 is not rejec! ted.If you want to drag a full essay, order it on our website: OrderEssay.net

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